b^2+7b-39=5

Solution for b^2+7b-39=5 equation:

Simplifying
b2 + 7b + -39 = 5

Reorder the terms:
-39 + 7b + b2 = 5

Solving
-39 + 7b + b2 = 5

Solving for variable 'b'.

Reorder the terms:
-39 + -5 + 7b + b2 = 5 + -5

Combine like terms: -39 + -5 = -44
-44 + 7b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
-44 + 7b + b2 = 0

Factor a trinomial.
(-11 + -1b)(4 + -1b) = 0

Subproblem 1
Set the factor '(-11 + -1b)' equal to zero and attempt to solve:

Simplifying
-11 + -1b = 0

Solving
-11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + -1b = 0 + 11

Combine like terms: -11 + 11 = 0
0 + -1b = 0 + 11
-1b = 0 + 11

Combine like terms: 0 + 11 = 11
-1b = 11

Divide each side by '-1'.
b = -11

Simplifying
b = -11
Subproblem 2
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Solution
b = {-11, 4}